Algorithm to display "n" natural numbers #c

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/* Algorithm For print "n" numbers */

1. Read the value of n.
2. i = 1
3. if ( i > n ) go to step 7
4. Display value of i
5. i = i + 1
6. go to step 3
7. Stop

/* Algorithm For print "n even" numbers */


1. Read the value of n.
2. i = 2
3. if ( i > n ) go to step 7

4. Display value of i
5. i = i +2
6. go to step 3
7. Stop

/* Algorithm For print "n odd" numbers */


1. Read the value of n.
2. i = 1
3. if ( i > n ) go to step 7

4. Display value of  i
5. i = (2n - 1)
6. go to step 3
7. Stop

Comments

  1. UnknownNovember 2, 2017 at 12:29 AM

    It is very very use ful

    ReplyDelete
  2. susanNovember 2, 2017 at 7:18 AM

    not so useful it should be more clear

    ReplyDelete
  3. SSSJanuary 18, 2018 at 5:03 AM

    Not understanding

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  4. UnknownJuly 16, 2018 at 9:27 PM

    odd no. programme is not right

    ReplyDelete
  5. UnknownJune 19, 2019 at 6:24 AM

    It's harder to understand please put in easily understood manner

    ReplyDelete
  6. ABDUL RASHEED AJJanuary 1, 2021 at 7:19 PM

    odd no. program is incorrect.. ( if n=3 it only print 1 1 1 )

    even no. program doesn't print n even no.s .. its only print upto n number... (if n=4 only print 2 4 and doesn't print 2 4 6 8)

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